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16x^2-33x+2=0
a = 16; b = -33; c = +2;
Δ = b2-4ac
Δ = -332-4·16·2
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-31}{2*16}=\frac{2}{32} =1/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+31}{2*16}=\frac{64}{32} =2 $
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